replaceAll()

This function replaces all substrings matching the given regular expression with a given replacement.


Bash
replaceAll(text, regex, replacement) #Output: Text


Examples

Parser expression

Description

Bash
replaceAll(" Hello World ", "\\s", "")


This example returns:

HelloWorld

All whitespace characters have been removed. 

\s is the regular expression equivalent for a whitespace.

Bash
replaceAll(" He__o Wor_d ", "_", "l")

This example returns:

Hello World

Additional information

Parameters used in this function

Parameter

Input (data type)

Description

text

text

Any given text.

regex

text

A valid

regular expression

that grabs all substrings to be replaced.

replacement

text

This text will replace all substrings found by the regex.

Output

This function returns a text

This expression could be used to e.g. modify an issue's summary or description.

If you want to replace only the first matching occurrence, have a look at the replaceFirst() function.

replaceFirst("Hello World", "l", "_")

replaceAll("Hello World", "l", "_")

"He_lo World"

"He__o Wor_d"

If you don't want to use a regular expression, have a look at the findReplaceAll() function.


📚 Use cases and examples