weekOfTheYear() | Decadis App Help Center

This function returns a number representing the week of the year of a given date in a certain time zone.

Bash

weekOfTheYear(timestamp, firstDayOfTheWeek, minimalDaysInFirstWeek, timeZone) #Output: Number

Examples

Parser expression	Description
Bash `weekOfTheYear(2023/01/03, {SUNDAY}, 1, LOCAL)`	This example returns: 1
Bash `weekOfTheYear(2023/01/03, {MONDAY}, 1, LOCAL)`	This example returns: 2
Bash `weekOfTheYear({issue.created}, {MONDAY}, 7, LOCAL)`	This example might return 20 if the issue was created in week 20.

Additional information

Parameters used in this function

Parameter	Input (data type)	Description
`timestamp`	number	The parameter must be valid timestamp. Usually this value is retrieved from a field (e.g. due date, created date).
`firstDayOfTheWeek`	number	The first day of the week, e.g.: `{SUNDAY}` in the U.S., and `{MONDAY}` in Germany. Both values are time macros.
`minimalDaysInFirstWeek`	number	The minimal number of days required in the first week of the year, e.g., if the first week is defined as the one that contains the first day of the first month of the year, value 1 should be used. If the minimal number of days required must be a full week (e.g. all days of the week need to be in that year), value 7 should be used.
`timeZone`	timezone	The time zone used for the calculation.

Days might depend on the time zone - it might be Sunday on the west coast of the US while at the same time it's already Monday in Australia.

Output

This function returns a number

📚 Use cases and examples

Use case	JWT feature	Workflow function	Field type	Automated action	Parser functions
Set a date on the same week day on alternate weeks		Update or copy field values			addDays() nextDayOfTheWeek() modulus() weekOfTheYear() datePart()