replaceAll() | Decadis App Help Center

This function replaces all substrings matching the given regular expression with a given replacement.

Bash

replaceAll(text, regex, replacement) #Output: Text

Parser expression	Description
Bash `%{replaceAll(" Hello World ", "\s", "")}`	This example returns: HelloWorld All whitespace characters have been removed. `\s` is the regular expression equivalent for a whitespace.
Bash `%{replaceAll(" He__o Wor_d ", "_", "l")}`	This example returns: Hello World

Parser expression

Description

Bash

%{replaceAll(" Hello World ", "\s", "")}

This example returns:

HelloWorld

All whitespace characters have been removed.

\s is the regular expression equivalent for a whitespace.

Bash

%{replaceAll(" He__o Wor_d ", "_", "l")}

This example returns:

Hello World

Parameters used in this function

Parameter	Input (data type)	Description
`text`	text	Any given text.
`regex`	text	A valid regular expression that grabs all substrings to be replaced.
`replacement`	text	This text will replace all substrings found by the given regex.

To insert a new line, simply press the Enter key.

This function returns a text

This expression could be used to e.g. modify an issue's summary or description.

If you want to replace only the first matching occurrence, have a look at the replaceFirst() function.

Parser expression	Value
Bash `%{replaceFirst("Hello World", "l", "_")}`	He_lo World
Bash `%{replaceAll("Hello World", "l", "_")}`	He__o Wor_d

If you don't want to use a regular expression, have a look at the findReplaceAll() function.

(books) Use cases and examples

Use case
No content found.